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Library · Traffic · How to run this

Northbeam new-vs-returning is not Triple Whale new-customer share

How to run thisTraffic3 steps
CalculatorNorthbeam new-vs-returning share · Calculator lives in the articleOpen

Put Northbeam new-customer $ over new $ + returning $. The quotient is new share %.

Pair: New-vs-returning share on Traffic. Other book: Triple Whale new-customer. Assist twin: assisted share.

What you type

New-customer $ — Northbeam dollars tagged new-customer in the named span.

Returning-customer $ — Northbeam dollars tagged returning in that same span.

New share % = new ÷ (new + returning) × 100. When new share % skews hard, revisit NC maps — never invent a new-share chip.

What not to do

Do not invent new share %. Do not drop a Triple Whale NC export into Northbeam fields. Do not treat assisted $ as new-customer $. Do not merge spans when one campaign owns the mix.

Related: Traffic, Triple Whale new-customer, assisted share, first-vs-last-touch.

Procedure

  1. Type new-customer $ and returning-customer $.
  2. Read new share %.
  3. Revisit NC maps when new share % is material.

Failure modes

  • Inventing new share %.
  • Dropping a Triple Whale NC export into Northbeam fields.
  • Treating assisted $ as new-customer $.

Worked example

None on this page yet. When one lands it will be a real case: what broke, the number, and what changed. Not a composite.

Glossary

New-vs-returning share %
New-customer $ ÷ (New-customer $ + Returning-customer $) × 100.

Work with us — We run this job on your accounts. Services

FAQ

Is this Triple Whale new-customer share?
Different attribution book. [New-customer share](/manuals/triple-whale-new-customer-share) puts NC $ over Triple Whale total. Here you put Northbeam new $ over new $ + returning $.
Is this Northbeam assisted share?
Sibling Northbeam grain. [Assisted share](/manuals/northbeam-assisted-share) is assisted credit. This page is new vs returning dollar mix.
What new share % should I invent?
None. Pull new-customer $ and returning-customer $ from the same Northbeam span.